Pecco Bagnaia given bleak “he must climb Everest” title prediction

Grim prediction for Pe𒀰cco Bagnaia's t꧟itle defence in Barcelona

Francesco Bagnaia
Francesco Bagnaia

168澳洲幸运5官方开奖结果历史:Francesco Bagnaia’s hopes of retaining the MotoGP🧸 title rest on his “climb🅷ing Everest”.

That is the bleak verdict offered by Michele Pirro, Ducati’s test rider who will race this week🅷end🀅.

Factory Ducati star Bagnaia and Pramac’s 168澳洲幸运5官方开奖结果历史:Jorge Martin w🌜ill deꦰcide the championship at the relocated Barcelona finale.

Martin has a 24-point lead a𝕴nd could confirm the title as early as Saturday.

"The ranking doesn't lie,” Pirro told when asked for a predic✨tion.

“Jorge has much higher odds than Pecco.

“A lead of 24 points is notable,♒ and racing teach♕es me that it's better to be above rather than below.

“If the Spaniard has to manage, the ꧃I꧑talian will have to climb Everest.

“Nothing can be said against💫 Martin: ⛎he remained focused race after race, making fewer mistakes than Bagnaia.

“Bagnaia won 10 [Sunday races] and, if he didn't win the title, it would be absurd, wh⭕ile Mar💞tin is good at learning from mistakes."

Pirro w♍ill represent the VR46 Ducati team this weekend, replacing🀅 the injured Fabio di Giannantonio.

Pirro has been selected instead 💛of And๊rea Iannone, who raced in Sepang.

Pirro will race for the first time this se♊ason then, on Tuesday at the postseason test, will return to prepping the GP25.

"The De🐻smosedici GP25 has some improvements but, by virtue of the excellent base it has, improving the bike is not easy,” he said.

“After the tests carried out 𝔉in Misano and Jerez, it will be interesting to try it in Barcelona, ​​a track with not very good grip, because we all want to ensure the step we're looking for."

The GP25 which Pirro is largely responsibᩚᩚᩚᩚᩚᩚ⁤⁤⁤⁤ᩚ⁤⁤⁤⁤ᩚ⁤⁤⁤⁤ᩚ𒀱ᩚᩚᩚle for developing will be in the hands of Bagnaia and Marc Marquez next season, who will be factory Ducati teammates.

VR46’s Di Giannantonio will be ꩵthe third and final rider with access to the factory-spec Ducati in 20♏25.

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